Concrete Column Axial and Moment Capacity


 

 

The MasterSeries Concrete Column design calculates the Axial and Moment Capacity for the provided reinforcement from first principles.  We carry out a rigorous analysis to determine the Axial load capacity for the applied moment (Nominal or real).

 

Note: In the following discussions and examples Fy is 460 and gm 0.95.  This is all still valid when Fy is 500 and gm 0.87.

 

Axial capacity Checks

 

Nuz is the design ultimate capacity of a section when subjected to axial load only.  This is used in calculation of deflection moments

 

Ncap is the design axial load capacity of a section as calculated below

 

 

For a column under Axial only

X     = D

Fs1 = Fy x .95  and

Fs2 = Fy x .95

 

Thus

Ncap = 0.9 x 0.45Fcu(Ac) + 0.95 x Fy x As

 

Short Columns

BS 8110 gives 2 formulas for the design of Short Braced Columns in 3.8.4.3. and 3.8.4.4.

 

N = 0.4fcuAc + 0.8Ascfy

 

N = 0.35fcuAc + 0.7Ascfy

 

These are simplified conservative equations which ignore any nominal moments.

 

General Design

 

In the MasterSeries we ignore the short column axial capacity equations.  Instead we always apply a nominal eccentricity to the column and carry out a rigorous analysis to determine the Axial load capacity for the applied moment (Nominal or real).

 

This is the real design check.  You will find that the column will always fail before you reach Nuz due to the moment.  See example below.

 

 

Example

                                        

Basic Data

          Design to          BS 8110: 1997                    

          Grades Fy, Fyv, Fcu          460 N/mm˛, 460 N/mm˛, 30 N/mm˛                    

Restraint Conditions and Effective Lengths

          x : for 400 mm deep column          Top:  Deep, Bottom:  Deep          1.20                    

          y : for 400 mm wide column          Top:  Deep,   Bottom:  Deep          1.20                    

          Lc=3500          Lox=3500-(950+950)/2          2550                              

          Loy=3500-(950+950)/2          2550                              

          Lex=3060.0 mm, Lex/h=7.7, exx=20.0 mm                                        

          Ley=3060.0 mm, Ley/b=7.7, eyy=20.0 mm                    

 

Uni-Axial , Short,  UnBraced,  Column Design

Critical Case : 1 : Dead plus Live

Axial Capacity

          Applied Axial N                    2527.0 kN          

          Nuz=.45•(B•H-acs)•fcu + .95•asc•fy          .45x(400x400-1608)x30 + 0.95x1608.0x460          2841.0 kN          OK

          Ncap=.9•.45•(B•H-acs)•fcu + .95•asc•fy.9x.45x(400x400-1608)x30 + 0.95x1608.0x460          2627.2 kN          OK

X-X Moments

          M nom          50.5                              

          Design Moment                    50.5 kNm          

Moment Capacity Mu X-X (For N = 2527 kN)

          Design Data X/h, h, b, X, Ac, Ybar          1.052, 400mm, 400mm, 420.7mm, 151462 mm˛, 189.3 mm                    

          Bar group1:M1 fn(bars,d,%,,la,F)3 x 16, 50.0, 0.308, 437, 150.0, 263.6          39.5 kNm          

          Bar group2:M2 fn(bars,d,%,,la,F)3 x 16, 350.0, 0.059, 118, -150.0, 71.0          -10.6 kNm          

          Bar group3:M3 fn(bars,d,%,,la,F)2 x 16, 200.0, 0.184, 367, .0, 147.7          0.0 kNm          

          Concrete Mc=(Ac•.45•fcu)•(H/2-Ybar)          (151462 x 0.45 x 30 ) x (400 / 2 - 189.3)          21.8 kNm          

          Mu =Mc + (M1+M2+M3)          21.8 + (39.5+-10.6+0.0)          50.7kNm          

          Max Moment/Mu          50.5 / 50.7          0.997          OK

          

 

 

 

By Hand, Check validity of computer Calcs.

 

Assuming X/h = 1.052 and X = 420.8 mm (outside section)

Prove                     Axial Capacity = N = 2527 kN and

                    Moment Capacity = 50.7 kNm as computed by computer

 

Bar Centres at  30 cover – 12 link – 16/2 bar = 50 mm in from face

 

Bar group1:  (Compression Face)

          3 x 16 = 603.2 mm2

          Cover 50  thus 420.8-50 = 370.8 from Neutral Axis

             Strain   = x0.0035 x 370.8/420.8 =  0.00308 strain

          Stress ,   x      x  .00308 = 616 N/mm2

          Limit 460 x  .95  = 437 N/mm2 max 

          Force F x A = 437 x 603.2 =                                                             263.6 kN             QED

          Moment about Centre of Column            

          La = 400/2-50 = 150          263.6 kN x 0.15                                        39.5 kNm           QED          

 

Bar group2:  (Tension Face)

          3 x 16 = 603.2 mm2

          Cover 50  thus 420.8 - 400 + 50 = 70.8 from Neutral Axis

             Strain   = x0.0035 x 70.8/420.8 =  0.00059 strain

          Stress ,   x      x  .00059 = 118 N/mm2           

          Force F x A = 118 x 603.2 =                                                               71.0 kN             QED                                         

          Moment about Centre of Column            

          La = 400/2-50 = 150          71.0 kN x -0.15 (on tension side >> La -ve)          -10.6 kNm           QED          

 

Bar group3:  (Mid Bars)

          2 x 16 = 402.1 mm2

          Cover 50  thus 420.8 - 200 = 220.8 from Neutral Axis

             Strain   = x0.0035 x 220.8/420.8 =  0.00184 strain

          Stress ,   x      x  .00184 = 367 N/mm2

          Force F x A = 367 x 402.1 =                                                               147.7 kN             QED                                         

          Moment about Centre of Column            

          La = 400/2-200= 0                    147.7 kN x -0.00                                        0.0 kNm           QED          

 

Concrete

          Dc = 0.9 X = 0.9 x 420.7 = 378.6 mm (if Dc > h then Dc = h)

          Force 0.45 x Dc x B x Fcu = .45 x 378.6 x 400 x 30                                2044.4 kN 

          Moment about Centre of Column            

          La = 400/2-378.6/2= 10.7 mm

          M = 2044.4 x 0.00107                                                                      21.8 kNm           QED

 

 

Axial Capacity = 263.6 +71.0 + 147.7 + 2044.4                                         2526.7 kN           QED          

                                                                                                    = N at 0.01% error

 

 Moment Capacity = 39.5 – 10.6 + 0 + 21.8                                        50.7 kNm           QED          

                                                                                                    = Mu

 

Reference: Kong & Evans: Reinforced and Prestressed Concrete, 3rd Edition.  Chapter 7